Base64 是很多人熟知的一种编码,它是一种基于可打印字符来表示二进制数据的方法,类似的还有 Base32、Base16 等 编码,区别就是选取的基不一样。
本文要讨论的是 Base58, 它更多的被用在比特币的钱包地址编码上,其 基 是58个字母和数字组成,列表如下:
123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz
注意,少了容易混淆的数字0,大写字母I,大写字母O,小写字母l,一共是: 10+26×2-4=58 个。
这个编码到底有什么好处呢?
- 首先,便于阅读,没有容易混淆的字母和数字
- 第二,没有标点符号 + 和 /,显的更美观
- 第三,整个成词,双击更容易选中,也不会随意折行
- 第四,这实际是一个混淆编码,看上去像Base64,但是其实不是,可以当作简单加密
附一份代码
import java.util.Arrays;
public class Base58 {
public static final char[] ALPHABET = "123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz".toCharArray();
private static final char ENCODED_ZERO = ALPHABET[0];
private static final int[] INDEXES = new int[128];
static {
Arrays.fill(INDEXES, -1);
for (int i = 0; i < ALPHABET.length; i++) {
INDEXES[ALPHABET[i]] = i;
}
}
/**
* Encodes the given bytes as a base58 string (no checksum is appended).
*
* @param input the bytes to encode
* @return the base58-encoded string
*/
public static String encode(byte[] input) {
if (input.length == 0) {
return "";
}
// Count leading zeros.
int zeros = 0;
while (zeros < input.length && input[zeros] == 0) {
++zeros;
}
// Convert base-256 digits to base-58 digits (plus conversion to ASCII characters)
input = Arrays.copyOf(input, input.length); // since we modify it in-place
char[] encoded = new char[input.length * 2]; // upper bound
int outputStart = encoded.length;
for (int inputStart = zeros; inputStart < input.length; ) {
encoded[--outputStart] = ALPHABET[divmod(input, inputStart, 256, 58)];
if (input[inputStart] == 0) {
++inputStart; // optimization - skip leading zeros
}
}
// Preserve exactly as many leading encoded zeros in output as there were leading zeros in input.
while (outputStart < encoded.length && encoded[outputStart] == ENCODED_ZERO) {
++outputStart;
}
while (--zeros >= 0) {
encoded[--outputStart] = ENCODED_ZERO;
}
// Return encoded string (including encoded leading zeros).
return new String(encoded, outputStart, encoded.length - outputStart);
}
/**
* Decodes the given base58 string into the original data bytes.
*
* @param input the base58-encoded string to decode
* @return the decoded data bytes
* @throws RuntimeException if the given string is not a valid base58 string
*/
public static byte[] decode(String input) throws RuntimeException {
if (input.length() == 0) {
return new byte[0];
}
// Convert the base58-encoded ASCII chars to a base58 byte sequence (base58 digits).
byte[] input58 = new byte[input.length()];
for (int i = 0; i < input.length(); ++i) {
char c = input.charAt(i);
int digit = c < 128 ? INDEXES[c] : -1;
if (digit < 0) {
throw new RuntimeException("Illegal character " + c + " at position " + i);
}
input58[i] = (byte) digit;
}
// Count leading zeros.
int zeros = 0;
while (zeros < input58.length && input58[zeros] == 0) {
++zeros;
}
// Convert base-58 digits to base-256 digits.
byte[] decoded = new byte[input.length()];
int outputStart = decoded.length;
for (int inputStart = zeros; inputStart < input58.length; ) {
decoded[--outputStart] = divmod(input58, inputStart, 58, 256);
if (input58[inputStart] == 0) {
++inputStart; // optimization - skip leading zeros
}
}
// Ignore extra leading zeroes that were added during the calculation.
while (outputStart < decoded.length && decoded[outputStart] == 0) {
++outputStart;
}
// Return decoded data (including original number of leading zeros).
return Arrays.copyOfRange(decoded, outputStart - zeros, decoded.length);
}
/**
* Divides a number, represented as an array of bytes each containing a single digit
* in the specified base, by the given divisor. The given number is modified in-place
* to contain the quotient, and the return value is the remainder.
*
* @param number the number to divide
* @param firstDigit the index within the array of the first non-zero digit
* (this is used for optimization by skipping the leading zeros)
* @param base the base in which the number's digits are represented (up to 256)
* @param divisor the number to divide by (up to 256)
* @return the remainder of the division operation
*/
private static byte divmod(byte[] number, int firstDigit, int base, int divisor) {
// this is just long division which accounts for the base of the input digits
int remainder = 0;
for (int i = firstDigit; i < number.length; i++) {
int digit = (int) number[i] & 0xFF;
int temp = remainder * base + digit;
number[i] = (byte) (temp / divisor);
remainder = temp % divisor;
}
return (byte) remainder;
}
}
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